X-2y=8 3x-2y=12 solving systems of linear equations

(2, -3)

Step-by-step explanation:

To solve a system of equations means to find the intersection point of the lines. For this system, you can use substitution.

Rearrange x-2y=8 so that "x" is by itself on one side.

x - 2y = 8

x = 8 + 2y (Use this equation for substitution because it equates to a variable)

In the other equation 3x-2y=12, substitute x for 8+2y.

3x - 2y = 12             Change x to the equation

3(8+2y) - 2y = 12     Use the distributive property and expand

24 + 6y - 2y = 12      Collect liked terms

24 + 4y = 12          

4y = 12 - 24          Subtract 24 from both sides to start isolating y

4y = -12                

y = -12/4            Divide 4 from both sides to isolate y

y = -3

Substitute y= -3 into any one of the equations. I will use x-2y=8.

x - 2y = 8       Change y to -3

x - 2(-3) = 8     Simplify

x - (-6) = 8

x + 6 = 8       Subtract 6 from both sides

x = 2

Therefore the solution is (2, -3).

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step-by-step explanation:

answer:

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