Solve the system of equations by the elimination method
7x-4y=-3
3x-9y=-45

x=3

y=6

Step-by-step explanation:

The goal of the elimination method is to cancel out one of the variables when the equations are added or subtracted. Let's say we will cancel out the two "x" first. Multiply both of the equations entirely so that the "x" is the same.

{7x - 4y = -3}  *3   =>     21x - 12y = -9

{3x - 9y = -45} *7   =>   21x - 63y = -315

Subtract the first equation from the second equation. Subtract each term separately and remember subtracting a negative number becomes adding.

.     21x - 12y = -9

-     21x - 63y = -315

.       0x + 51y = 306   Notice x variable cancels out

.               51y = 306    <= Divide both sides by 51

.                   y = 6

Substitute y=6 into any of the equations. Then isolate x. I will use 7x-4y=-3 .

7x - 4y = -3

7x - 4(6) = -3    <=simplify

7x - 24 = -3       Start isolating x by bringing everything to the right side

7x = -3  + 24    <=add 24 to both sides. This cancels out 24 on the left.

7x = 21       <=divide both sides by 7

x = 3

The solution of the system is (3, 6).

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.

none cuz there are no "following statements" regarding the question

step-by-step explanation: