I'm not sure how to do this. include steps. will give if !

30 gallons of first brand & 20 gallons of second brand

Step-by-step explanation:

Let the amount in gallons of 65% antifreeze needed be x.

Let the amount in gallons of 90% antifreeze needed be y.

You need to make a total of 50 gallons, so that gives us our first equation:

x + y = 50

Now we deal with the amount of pure antifreeze in each amount of antifreeze and in the result.

x gallons of 65% antifreeze contain 0.65x gallons of pure antifreeze.

y gallons of 90% antifreeze contain 0.9x gallons of pure antifreeze.

The result is 50 gallons of 75% pure antifreeze which contains 0.75 * 50 gallons of pure antifreeze. 0.75 * 50 = 37.5

Now we add the two amounts of pure antifreeze and set equal to the result.

0.65x + 0.9y = 37.5

This is the second equation. We have a system of two equations in two unknowns.

x + y = 50       Equation 1

0.65x + 0.9y = 37.5        Equation 2

Multiply the first equation by -0.65

-0.65x - 0.65y = -32.5

0.65x + 0.9y = 37.5    This is Equation 2.

Add the two equations above to eliminate x.

0.25y = 5

y = 20

Substitute 20 for y in the original equation and solve for x.

x + y = 50

x + 20 = 50

x = 30

30 gallons of first brand & 20 gallons of second brand

jml angle lkj & angle mj = lm

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: