Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.

y−3=4(x−6)

y−3=−14(x−6)

y−6=4(x−3)

y−6=−14(x−3)

For this case we have that by definition, the equation of a line in the point-slope form is given by:

Where:

m: It is the slope of the line and is a point through which the line passes.

We have the following equation of the slope-intersection form:

Where the slope is

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

Thus, the equation will be of the form:

Finally we substitute the given point and we have:

Option B

1. 180°. the sum of the interior angles of a triangle is 180°, for the equilateral triangle that it has three equals side is 60°+60°+60°=180°.

2. 60°. each interior angle of a equilateral triangle is 60°

3. 120°. the measure of ∠m is 120°, the sum of the angles ∠m and ∠n is equal to 180°. so, in order to find the measure of ∠m, we have ∠m+∠n=180° > ∠m=180°-∠n > ∠m=180°-60°=120°.

4. 360°. the sum of the exterior angles of an equilateral triangle is ∠m+∠r+∠x=120°+120°+120°=360°. the exterior angles of any triangle always add 360°.