The amount of a radioactive substance remaining after t years is given by the function , where m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60 sample remaining after 10 years, and approximately how many milligrams remain?

; 13.5 mg
; 34.6 mg
; 0.2 mg
; 4.6 mg

13.5 mg

Step-by-step explanation:

Here given Cobalt isotope has half life of 5.3 years.

Initial amount is 50 mg.

Given time(10 years) is roughly equals to two half life.

So, after 5.3 year 25 mg of isotope will left further in next half life only around 12.5 mg remains.

Among options 13.5 mg is the best possible

(8+64)^2= 5184 < answer

step-by-step explanation:

2^3 = 8

4^3= 64

(8+64)^2 = 5184