Aset of x and y scores has a regression equation with a slope of b = 4. if the mean for the x values is mx = 2 and the mean for the y values is my = 6, what is the y-intercept value for the regression equation?

The Y-intercept value for the regression equation is -2

Step-by-step explanation:

The linear regression has the form: y = a + b*x, where a is the Y-intercept and b is the slope. To find the a compute the following:

a = MY - b*MX

where MX and MY denotes mean for the X and the Y respectively. Replacing:

a = 6 - 4*2 = -2

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).