Write an equation in slope-intercept form of the line that passes through the points (8,2) and is parallel to the graph of the equation y=4x-3.

Slope-intercept form  is   y= 4x - 30

Step-by-step explanation:

Step 1: Substitute the slope from original line into the equation of the line

Here slope , m is 4

y= mx +b

where

m is the slope

b is the y intercept

So Substituting slope we get,

y= 4x +b(1)

Step 2 :Substitute the given point (8,2) into the x and y values  of equation (1)

y = 4x +b

2 =4(8) + b

Step 3: Solve for y intercept values

2 = 32+ b

2-32 =b

-30 =b

Now the y intercept value b= -30

Step 3:  Substitute this value for 'b' in the slope intercept form equation

Substituting the value  in eq (1) we get,

y= 4x +(-30)

y= 4x - 30

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: