(a) let (x, y ) denote a uniformly chosen random point inside the unit square [0, 1]2 = [0, 1] × [0, 1] = {(x, y) : 0 ≤ x, y ≤ 1}. let 0 ≤ a < b ≤ 1. find the probability p(a < x < b), that is, the probability that the x-coordinate x of the chosen point lies in the interval (a, b). (b) what is the probability p(|x − y | ≤ 1/4)?

the bottom of the spinner is not flat.

step-by-step explanation:

the diameter is 16 cm. are you a teacher?

step-by-step explanation:

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16