in a word processing document or on a separate piece of
paper, use the guide to construct a two column proof
proving that triangle adc is congruent to triangle cba
given that 2d and zb are right angles and dc is parallel
to ab. submit the entire proof to your instructor.

Proof is given below.

Step-by-step explanation:

Given:

∠ D and ∠ B are right angles

DC || AB

To Prove:

Δ ADC ≅ Δ CBA

Proof:

In  Δ ADC and Δ CBA

1. ∠ D and ∠ B are right angles      ……….{GIVEN}

2. ∠ ACD ≅ ∠ CAB    …{if lines are parallel then alternate interior angle are equal}

3. AC ≅ AC     ……….{ Reflexive property ( common Hypotenuse)}

4. Δ ADC ≅ Δ CBA ….{Hypotenuse-Angle-theorem test}

Proof is given below.

Step-by-step explanation:

Given:

∠ D and ∠ B are right angles

DC || AB

To Prove:

Δ ADC ≅ Δ CBA

Proof:

In  Δ ADC and Δ CBA

1. ∠ D and ∠ B are right angles      ……….{GIVEN}

2. ∠ ACD ≅ ∠ CAB    …{if lines are parallel then alternate interior angle are equal}

3. AC ≅ AC     ……….{ Reflexive property ( common Hypotenuse)}

4. Δ ADC ≅ Δ CBA ….{Hypotenuse-Angle-theorem test}

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13