Arandom survey of teachers found that 224 of 395 elementary school teachers, and 126 of 266 high school teachers, were very satisfied with their work. find a 95% confidence interval for the difference (elementary minus high school) in proportions of teachers who are very satisfied with their work.

95% confidence interval would be (0.013,0.167).

Step-by-step explanation:

Since we have given that

survey of teachers found that 224 of 395 elementary school teachers,

So, n₁ = 395

x₁ = 224

So,

n₂ = 266

x₂ = 126

So,

At 95% confidence level, z = 1.96

So, interval would be

Hence, 95% confidence interval would be (0.013,0.167).

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25