Here's a graph of a linear function. write the
equation that describes that function.
xpress it in slope-intercept form.

First you need to find the y-intercept, which is y = -1

Next is we need to find the slope of the line > you are going to have to do this by finding to clear point

The ones that I will be using are: (3, 1); (6, 3)   (You could take any points)

Now using the slope formula we could find m.

m = y2-y1 / x2-x1

(1 - 3) / (3 - 6) = m

-2 / -3 = m

m = 2/3

Using the linear function format: y = mx + b

Therefore the equation of the line is y = 2x/3 -1

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

486in is correct

step-by-step explanation: