Is (x-1) a factor of x^100+4x^99+3? can you show steps

The answer is no because .

Step-by-step explanation:

If is a factor of , then .

Let's check.

Since , then is not a factor of .

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So anyways more on how this works:

If where is the remainder and is the quotient of the division, then multiplying both sides by gives .

We see that is a factor if the remainder is 0. (Just like we know 2 is a factor of 6 because when we divide 6 by 2 we get a remainder of 0.)

Anyways if we evaluate for we get:

So evaluating for will tell us the remainder of the quotient without actually performing division.

The remainder will tell us if is a factor of

If the remainder is 0, then the answer is yes.

If the remainder is not 0, then the answer is no.

(The question to be answer "Is this a factor of this?")

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

stops on an even number.