Two sides of a right triangle measures 2 units and 4 units. what is the area of the square that shares a side with the third side of the triangle?

Part 1) The area of the square is 20 square units

Part 2) The area of the square is 12 square units

Step-by-step explanation:

In this problem we have two cases

Part 1) The third side of the right triangle is the hypotenuse

so

we have

c is the hypotenuse (third side)

The area of the square is equal to length of the third side squared

Applying  Pythagorean Theorem

substitute the given values

The area of the square is 20 square units

Part 2) The third side of the right triangle is a leg

so

we have

b is a leg  (third side)

The area of the square is equal to length of the third side squared

Applying  Pythagorean Theorem

substitute the given values

The area of the square is 12 square units

2? if not the correct answer you might need to provide more information

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0