Parker has a part-time job picking apples. let the random variable a represent the number of baskets of apples picked each day. the distribution of a has mean 4.5 baskets and standard deviation 1.3 baskets. parker is paid $65 per day plus $5 per basket. what are the mean μ and standard deviation σ of parker’s daily pay?

a=μ=$87.50 and σ=$71.50

b=μ=$87.50 and σ=$6.50

c=μ=$22.50 and σ=$6.50

d=μ=$87.50 and σ=$1.30

e=μ=$22.50 and σ=$71.50

The correct answer is B. μ = US$87.50 and σ = US$6.50

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of baskets of apples picked each day by Parker = A

Mean of A = 4.5 baskets

Standard deviation = 1.3 baskets

Daily payment received by Parker = US$ 65 + US$ 5 per basket

2. What are the mean μ and standard deviation σ of Parker’s daily pay?

Let's find out the mean and standard deviation of Parker's daily pay:

Daily payment received by Parker = US$ 65 + US$ 5 per basket

Daily payment mean received by Parker = 65 + 5 * 4.5

Daily payment mean received by Parker = 87.5

Standard deviation in US$ = 1.3 * 5

Standard deviation in US$ = 6.5

The correct answer is B. μ = US$87.50 and σ = US$6.50

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

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step-by-step explanation: vsfdvsfvd