Mathematics, 12.12.2019 21:31 dayi80

factor completely.

-2k - k 3 - 3k 2

k(-k + 1)(k - 2)
-k(k - 1)(k - 2)
-k(k + 1)(k + 2)

Answers: 3

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factor completely.

-2k - k 3 - 3k 2

k(-k + 1)(k - 2)
-k(k - 1)(k - 2)<...

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More questions: Mathematics Another questions

factor completely. -2k - k 3 - 3k 2 k(-k + 1)(k - 2) -k(k - 1)(k - 2) -k(k + 1)(k + 2)

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Another question on Mathematics

factor completely.

-2k - k 3 - 3k 2

k(-k + 1)(k - 2)
-k(k - 1)(k - 2)
-k(k + 1)(k + 2)