Suppose the height of an 18 year old boy is normally distributed with mean 187cm fifteen percent of 18 year old boys have heights greater than 193cm. find the probability that two 18 year old boys chosen at random will have heights greter than 185cm

the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403

Step-by-step explanation:

P( x > 193) = 0.15

= 1- p(x less than or equal 193)

= 1 -p( z < (x- u) /sigma)

= 1- p( z< (193 - 187)/ sigma)

= 1- p( z< 6/ sigma)

P(z< 6/sigma) = 1 - 0.15

P(z < 6/sigma)= 0.85

6/sigma =1.036

Sigma= 6/1.036

Sigma= 5.79

P( x> 185) = 1- p( x< 185)

= 1- p (z < (185- 187)/5.79)

= 1- p( z< -0.345)

= 1- 0.365

= 0.635

P (x> 185) = 0.635 × 0.635

=0.403

answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00