Consider this system of linear equations:
22x − y = -23 (equation 1)
11x + 12y = 1 (equation 2)
to find the value of x, you need to substitute x = (y - 23)/22 x = (y + 23)/22 y = 22x + 23 y = 22x - 23 in equation 2.
the value of x is -1 22/23 1 2 .

If you would like to find the value of x, you can do this using the following steps:

22x - y = -23 ... 22x = y - 23 ... x = (y - 23) / 22
11x + 12y = 1

11 * (y - 23) / 22 + 12y = 1
(y - 23) / 2 + 12y = 1
y - 23 + 24y = 2
25y = 2 + 23
25y = 25
y = 1

x = (y - 23) / 22 = (1 - 23) / 22 = - 22 / 22 = - 1

The correct result would be: x = -1, y = 1.

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