Given f(x) = cos(x) and x =π/6
t2(x)= (√3//2)(x-(π//4)√3(x-(π/6)2)

let a be a positive real number and let j be the closed interval [(π/6)-a,(π/6)+a] use theuse the quadratic approximation error bound to verify that
a. |f(x)−t2(x)|≤ a3/3! for all x in j.
use this error bound to find a value of a so that
b. |f(x)−t2(x)|≤ 0.01 for all x in j. (round your answer to six decimal places.)
a=

answer: idk

step-by-step explanation:

right

step-by-step explanation:

41*67/2=1373.5

step-by-step explanation:

i just used a calculator

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116