The solid graph is a translation of rootindex 3 startroot x endroot. on a coordinate plane, 2 cube root functions are shown. the first has equation f (x) and is represented by a dashed line. it goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes through (8, 2). the second function goes through (negative 8, 0), has an inflection point at (0, 2), and goes through (8, 4). how was the graph of rootindex 3 startroot x endroot shifted to form the translation? 2 units up 2 units down 2 units left 2 units right

2 units up.

Step-by-step explanation:

If you take a look at the graph, it shows that it is 2 units up from where it initially started, therefore it is moved 2 units up. It says the SOLID graph is the translation, therefore it would be moving 2 units up.

2 units up

Step-by-step explanation:

There is no left or right translation so this makes it easy for us. It clearly shifts two points/units up, so you are automatically finished with this answer!

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what is the image?

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length