Consider these relations on the set of real numbers:

r1 = {(a, b) ∈ r2 ∣ a > b}, the greater than relation,

r2 = {(a, b) ∈ r2 ∣ a ≥ b}, the greater than or equal to relation,

r3 = {(a, b) ∈ r2 ∣ a < b}, the less than relation,

r4 = {(a, b) ∈ r2 ∣ a ≤ b}, the less than or equal to relation,

r5 = {(a, b) ∈ r2 ∣ a = b}, the equal to relation,

r6 = {(a, b) ∈ r2 ∣ a ≠ b}, the unequal to relation.

find: 9.1 34-36r1 u r3r2 ∩r4.r2 − r1r3⊕r5r4 ∩r6r1◦r2r1◦r6r2◦r3

may i see the picture? it would a lot, xox

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61

the median is   36 orr sum like dat

step-by-step explanation:

question 1: step-by-step explanation:

1/4 of 84 = 84÷4= 21