Given: cp is perpendicular to ab, cp bisects ab, prove: ca=cb

Proved   CA=CB

Step-by-step explanation:

Given,

In ΔABC,  CP is perpendicular to AB.

And CP bisects AB.

So,  AP=PB   and   ∠CPA=∠CPB=90°

The figure of the triangle is in the attachment.

Now, In ΔACP and ΔBCP.

AP = PB(given)

∠CPA = ∠CPB = 90°(perpendicular)

CP = CP(common)

So, By Side-Angle-Side congruence property;

     ΔACP ≅ ΔBCP

According to the property of congruence;

"If two triangles are congruent to each other then their corresponding sides are also equal."

Therefore,  CA = CB (corresponding side of congruent triangle)

CA = CB  Hence Proved

sine

step-by-step explanation:

no he doesnt because "-16' is negatiive

step-by-step explanation: