The sum of three numbers is 108. the second number is 4 times the third. the first number is 6 more than the third. what are the numbers?

The numbers are 23, 68 and 17.

Step-by-step explanation:

Given:

The sum of three numbers is 108.

The second number is 4 times the third.

The first number is 6 more than the third.

Now, to find the numbers.

Let the third number be .

The second number be .

And the first number be .

According to question:

Now adding the variables we get:

⇒

Subtracting both sides by 6 we get:

⇒

Dividing both sides by 6 we get:

⇒

Third number =  

Second number =  

First number =

Therefore, the numbers are 23, 68 and 17.

could you provide figure.

you just switch the numbers basically so it would be 3/17