Dean won a trip to the upcoming winter olympics and needs to plan which events to attend. during the first week of competition, preliminary rounds of speed skating, ice hockey, and cross-country skiing will be taking place. if dean plans to attend one round of each of these events, in how many different orders could he view them?

6 different orders

Step-by-step explanation:

Given:

Number of events taking place = 3 (Speed skating, ice hockey and cross-country skiing)

Now, Dean plans to attend ne round from each one of them.

The questions asks us to find the different orders in which Dean can attend each event.

So, this is a question of permutations as order of events is important here.

So, number of ways to attend 1 event out of 3 events is 3.

Now, there are 2 events left. Number of ways of attending 1 event out of the remaining two events is 2 ways.

Now, only one event will be left. So, Dean will finally attend that event.

Thus, total number of different orders in which Dean can attend one round of all the 3 events is given as:

Hence, Dean can attend each of the three events in 6 different orders.

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation: