Given the force field f, find the work required to move an object on the given orientated curve. bold upper f equals left angle y comma x right anglef=y, x on the parabola y equals 6 x squaredy=6x2 from (0 comma 0 )(0,0) to (2 comma 24 )(2,24).

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

35 is an outlier

step-by-step explanation:

answer: im gonna go with milli

step-by-step explanation: