The null and alternate hypotheses are:

h0: μ1 ≤ μ2
h1: μ1 > μ2
a random sample of 29 items from the first population showed a mean of 112 and a standard deviation of 9. a sample of 15 items for the second population showed a mean of 97 and a standard deviation of 12. use the 0.10 significant level.
a. find the degrees of freedom for unequal variance test. (round down your answer to the nearest whole number.)
b) state the decision rule for 0.100 significance level. (round your answer to 3 decimal places.)
reject h0 if t >
c) compute the value of the test statistic
d) what is your decision regarding the null hypothesis? use the 0.10 significance level.

Step-by-step explanation:

Given that the  null and alternate hypotheses are:

H0: μ1 ≤ μ2

H1: μ1 > μ2

Group   Group One     Group Two  

Mean112.0097.00

SD9.0012.00

SEM1.673.10

N29    15    

The mean of Group One minus Group Two equals 15.00

a) df = 42

 standard error of difference = 3.212

 b) Reject H0 if t statistic >1.302

  t = 4.6699

 Since t > 1.302, we reject null hypothesis

It is evident that the mean I is greater than mean 2.

step-by-step explanation:

bob the banana

segment bisector

step-by-step explanation:

line segment bisector. definition: a line, ray or segment which cuts another line segment into two equal parts. try this drag one of the orange dots at a or b and note the the line ab always divides the line pq into two equal parts.

mark brainliest!