Arectangle has a perimeter of 42 feet. its length, l, is three feet more than twice its width, w. create a equation that relates l and w based on the length being three feet more than twice the with

W = 6 feet

L = 15 feet

Step-by-step explanation:

The perimeter of the rectangle is the length of the outer boundary.

If length is defined as L and width is defined as D,

Perimeter = 2(L + W)

Perimeter is given to be 42 feet.

2(L + W) = 42

(L + W) = 21           (1)

Also , Its length, L, is three feet more than twice its width, W.

L = 2W  + 3           (2)

Solve (1) and (2) ,

3W + 3 = 21

W = 6 feet

L = 15 feet

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