The shadow of the moon during a solar eclipse travels 2300 miles in one hour in the first 20 minutes the shoadow traveled seven 66 2/3 miles how long does it take for the shadow to reach 1150 miles

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

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