On a very hot summer day, 5 percent of the production employees at midland states steel are absent from work. the production employees are randomly selected for a special in-depth study on absenteeism. what is the probability of randomly selecting 10 production employees on a hot summer day and finding that none of them are absent? a. 60b. 65c. 70d. 75

a) 60%

Step-by-step explanation:

This problem can be solved through binomial probability

Let's say probability of success is the probability of absent

p = 5% = 0.05

Probability of failure

q = 1-p = 0.95

The number of trial in this case is the number of employees randomly selected

n = 10

Since we are looking for 0 absent employee, we are looking for the probability that the success is nil (i.e 0)

x = 0

Binomial therorem

B(n,x,p) = B(10,0,0.05)

= C(10,0) * p^x * q^(n-x)

= 1 * (0.05^0) * (0.95^10)

= 1 * 1 * 0.95^10

= 0.59873693923

= 0.6 or 60%

i hope this is what you were looking for.

see attached graph