Pentagon pqrst and its reflection, pentagon p'q'r's't', are shown in the coordinate plane below:
pentagon pqrst and pentagon p prime q prime r prime s prime t prime on the coordinate plane with ordered pairs at p negative 4, 6, at q negative 7, 4, at r negative 6, 1, at s negative 2, 1, at t negative 1, 4, at p prime 4, 6, at q prime 7, 4, at r prime 6, 1, at s prime 2, 1, at t prime 1, 4.
what is the line of reflection between pentagons pqrst and p'q'r's't'?
x = 0
y = x
y = 0
x = 1

Yes, the answer is A. x=0. Another way to say "reflect across the y-axis" is to say "reflect across the line x=0" since the line created by graphing x=0 is the same as the y-axis. An image that is a reflection across the y-axis, or across the line x=0, will have opposite x-coordinates from the pre-image but identical y-coordinates. In other words, the x value points just changed signs from negative to positive values since it went through the rule (x, y) → (−x, y).

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.