What is a value after 7 years of a car that originally cost $25000 if it depreciates at a rate of 8% per year

original cost times 8%

$25,000 x .08 = $2,000

then take $25,000 - $2,000 = $23,000 (first year depreciation)

continue with 2nd year

$23,000 x .08 = $1840

23000-1840 = 21160 (2nd year depreciation)

21160 x .08 = 1693

21160 - 1693 = 19467 (3rd year depreciation)

19467 x .08 = 1557

19467 - 1557 = 17910 (4th year depreciation)

17910 x .08 = 1433

17910 - 1433 = 16477 (5th year depreciation)

16477 x .08 = 1318

16477 - 1388 = 15159 (6th year depreciation)

15159 x .08 = 1213

15159 - 1213 = 13946 (7th year depreciation)

Step-by-step explanation:

Asset Value x Annual Percentage  = Depreciation Amount

Asset Value - Depreciation Value  = Balance

-6 + 3 = 3 - 6

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2