Two cows start walking in opposite direction from the same starting point. one cow has 4 legs, the other cow has 2 legs. the rate of the cow with 2 legs is 10 mph les than the rate of the other cow. after 10 hours, the cows were 500 miles apart. find the rate of each cow.

the speed if the 4 legged cow is 30 mph while the speed of the 2 legged cow is 20 mph

Step-by-step explanation:

One cow has 4 legs, the other cow has 2 legs.

Let x represent the speed of the cow with with four legs.

Let y represent the speed of the cow with 2 legs.

The rate of the cow with 2 legs is 10 mph less than the rate of the other cow. This means that

y = x - 10 - - - - - - - 1

Distance = speed × time

After 10 hours, the cows were 500 miles apart.

Distance travelled by the 4 legged cow is

x × 10 = 10x mph

Distance travelled by the 2 legged cow in 10 hours is

y × 10 = 10y mph

Since they are 500 miles apart, it means that the total distance covered by both cows is 500 miles. Therefore,

10x + 10y = 500

x + y = 50 - - - - - - - 2

Substituting equation 1 into equation 2, it becomes

x + x - 10 = 50

2x = 50 + 10 = 60

x = 60/2 = 30

y = x - 10

y = 30 - 10 = 20

there will be 35 boys in each team. : )

i honestly dont know