If you have 9 quaters and 21 pennies, in percents, what is the chance that you will pick a penny out is a hat?

We know that you have 9 quarters

We also know that you have 21 pennies

Probability is represented as "determined factor" / total

First, we need to find the total amount of possibilities. This means that you have to add 21 and 9

21 + 9 = 30

We want to know the probability of picking a penny out of the hat, so you would represent this as:

21/30

To turn it into a percent, divide 21 by 30.

21 ÷ 30 = 0.7

0.7 is equivalent to 70% as a percent

This means that you will have a 70% chance of picking a penny out

70%

answer: i think you should do the math and pay attention in class : )

step-by-step explanation:

that is truly what   think but if i get the answer i will

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.