Tickets to the college basketball game are $2.50 for students and $3 for general admission. if 54 people attended the last game and the box office collected $149, how many of each type of ticket did they sell?

Step-by-step explanation:

Let g represent the number of general admission tickets sold. Then the revenue is ...

  3g +2.50(54-g) = 149

  .50g = 14 . . . . . . . . . . . subtract 135

  g = 14/.5 = 28 . . general admission tickets sold

  54-g = 26 . . . . . student tickets sold

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

idk man good luck man