Arectangular sheet of cooper is twice as long as it is wide. from each corner a 3-inch square is cut out, and the ends are then turned up to form a tray. if the volume of the tray is 324 cubic inches , what were the original dimensions of the sheet of cooper?

length=24 inches and width=12 inches

Step-by-step explanation:

Let width of the rectangular sheet be x.

Then its length is twice as width = 2x

From each corner 3-inch square is cut to form a tray.

The length of the tray formed = l = 2x-6 (total length - length of 2 squares cut out from both ends)

The width of the tray formed  = b = x-6 (total width - length of 2 squares cut out from both ends)

Height of the tray formed = h = 3 inches

Volume of the tray = l*b*h = (2x-6)*(x-6)*3 = 324 cubic inches.

The length and width of the sheet is 24 and 12 inches respectively.

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

35-60 students are taking math.