Find the sum of all solutions to the equation $3x(x+4) = 66$.

the solutions are:

and the sum of solutions is:

-4

Step-by-step explanation:

the expression is:

doing the multiplication

dividing everything by 3:

we use the quadratic formula to find the solutions:

in this case since we have an equation in the form

where

the quadratic formula is:

from this, using the + sign we find the first solution:

and the second solution:

the sum of the solutions is:

597

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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