3consecutive odd integers that the sum of the smallest and 4 times the largest is 61

  9, 11, 13

Step-by-step explanation:

Let n represent the smallest of the integers. Then n+4 is the largest of them. The given total is ...

  n + 4(n+4) = 61

  5n +16 = 61

  5n = 45 . . . . . . subtract 16

  n = 9 . . . . . . . . divide by 5

The smallest of the integers is 9, so the other two are 11 and 13.

x = -5

step-by-step explanation:

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!