Find the equation of the line parallel to the line graphed that passes through the point (6,-1). a) y = 1 3 x + 1 b) y = - 1 3 x + 1 c) y = - 1 3 x + 6 d) y = - 7 6 x + 6

(6,1)(5,4)slope = (4 - 1) / (5 - 6) = 3/-1 = -3y = mx + bslope(m) = -3use either of ur , = 6 and y = 1now sub and find b, the y int1 = -3(6) + b1 = -18 + b1 + 18 = b19 = bso ur equation is : y = -3x + we need it in standard formy = -3x + 3x to both sides3x + y = 19 < == standard form

Remember, you can do anything to an equation as long as you do it to both sidesminus 36 from both sides4.5(8-x)=66-2.5(3x+24)distribute36-4.5x=66-7.5x-60add like terms36-4.5x=-7.5x+6add 7.5x to both sides36+3x=6minus 36 from both sides3x=-30divide both sides by 3x=-10