Suppose that prices of a gallon of milk at various stores in one town have a mean of $3.73$⁢3.73 with a standard deviation of $0.10$⁢0.10. using chebyshev's theorem, what is the minimum percentage of stores that sell a gallon of milk for between $3.43$⁢3.43 and $4.03$⁢4.03? round your answer to one decimal place.

At-least 88.89%

Step-by-step explanation:

As per given , we have

Population mean :

Standard deviation :  

Now , $3.43= $⁢3.73- 3(0.10) =

$⁢4.03 = $⁢3.73+3(0.10) =

i.e. $3.43 is 3 standard deviations below mean and $⁢4.03 is 3 standard deviations above mean .

To find :  the minimum percentage of stores that sell a gallon of milk for between $3.43 and $4.03.

i.e. to find minimum percentage of stores that sell a gallon of milk  lies within 3 standard deviations from mean.

According to Chebyshev, At-least of the values  lies with in from mean.

For k= 3

At-least of the values lies within from mean.

In percent =

Hence, the minimum percentage of stores that sell a gallon of milk for between $3.43 and $4.03 =  At-least  88.89%

idk

step-by-step explanation: i just don't

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places