In the nationwide poll of n = 1,100 adults, 38% said that they favored legalization. the margin of error for the 95% confidence level was given as 3%. (a) find a 95% confidence interval estimate of the percentage of american adults who favored the legalization of marijuana at the time of the poll.

(35% , 41%)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

, where = sample proportion.

and E = margin of error.

Given : The percentage of adults favored legalization :

Margin of error for the 95% confidence level : E= 3%

Then, the 95% confidence interval estimate of the percentage of American adults who favored the legalization of marijuana at the time of the poll. will be :

(38%-3% , 38%+3%)= (35% , 41%)

Hence, the 95% confidence interval estimate of the percentage of American adults who favored the legalization of marijuana at the time of the poll = (35% , 41%)

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

yes, gavin is right.

step-by-step explanation:

gavin is correct. 

this problem is about converting 9% per year to how many percent per quarter. the rate is still the same. it only differed in the time period. so, through dimensional analysis,

9% per year  × (1 year / 4 quarters) = 2.25% per quarter

if he was asked to convert 9% per year to how many percent per quarter  compounded quarterly, then you will not simply divide by four. this is because compounding is not linear.

hope this , have a good day. c;