The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of asian postmenopausal women who were vegans and another sample of such women who were omnivores. diet sample size sample mean sample sd vegan 85 5.10 1.05 omnivore 96 5.55 1.20 calculate a 99% ci for the difference between population mean total cholesterol level for vegans and population mean total cholesterol level for omnivores. (use μvegan − μomnivore. round your answers to three decimal places.)

99% CI:

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

The MSE can be calculated as

The weighted sample size nh can be calculated as

The standard deviation then becomes

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

Then the confidence interval can be constructed as

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

answer: y=4000x+14000

step-by-step explanation: