La correa transportadora de una estación automática levanta 500 toneladas de mineral hasta una altura de 90 ft en una hora. ¿qué potencia en caballos de fuerza se requiere para esto?

Step-by-step explanation:

500 ton = 500000 kg

90 ft = 27,4 m

1 h = 3600 s

P = m g h / t = 500000 kg . 9,80 m/s² . 27,4 m / 3600 s ≈ 37300 W

P = 37300 W . 1 HP / 744,8 W = 50 HP

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!