Find the value of y for the following system of equations 5x + 3y = 10 x = y - 6

x = -1 , y = 5

Step-by-step explanation:

Solve the following system:

{5 x + 3 y = 10 | (equation 1)

x = y - 6 | (equation 2)

Express the system in standard form:

{5 x + 3 y = 10 | (equation 1)

x - y = -6 | (equation 2)

Subtract 1/5 × (equation 1) from equation 2:

{5 x + 3 y = 10 | (equation 1)

0 x - (8 y)/5 = -8 | (equation 2)

Multiply equation 2 by -5/8:

{5 x + 3 y = 10 | (equation 1)

0 x+y = 5 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x+0 y = -5 | (equation 1)

0 x+y = 5 | (equation 2)

Divide equation 1 by 5:

{x+0 y = -1 | (equation 1)

0 x+y = 5 | (equation 2)

Collect results:

{x = -1 , y = 5

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

idk u tell me

step-by-step explanation: