Water flows straight down from an open faucet. the cross-sectional area of the faucet is 1.9 × 10-4m2 and the speed of the water is 0.75 m/s as it leaves the faucet. ignoring air resistance, find the cross-sectional area of the water stream at a point 0.10 m below the faucet.

Step-by-step explanation:

To find the cross-section area at a point below the faucet

we can use following equations

and equation of continuity

v_1= velocity at the out let

v_2=  velocity at the inlet (faucet)= 0.75 m/s

y = distance below the faucet = 0.10 m

A_1= cross-sectional area of the water stream at a point 0.10 m below the faucet.

A_2= area of faucet= 1.9 × 10-4m2

from above two equation we can write

now putting the values we get

A_1= 0.00008=

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system