Mathematics, 18.12.2019 04:31 MegRasmussen31

3. a scuba diver is 15.5 feet below the
surface of the water. if the diver
continues to swim downward at a rate
of 2.5 feet per second, what integer
represents her location relative to the
surface after 7 seconds? how far does
the diver have to go to return to the
surface?
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Answers: 3

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Answers

Answer from: imello51

The answers are:

33 is the integer that represents her location relative to the surface after 7 seconds.

And 33 feet far the diver have to go to return to the surface.

Step-by-step explanation:

Given:

A scuba diver is 15.5 feet below the surface of the water.

The diver continues to swim downward at a rate of 2.5 feet per second.

Now, to find the integer represents her location relative to the surface after 7 seconds.

And to find how far does the diver have to go to return to the surface.

So, to get the integer represents her location relative to the surface after 7 seconds.

Initial depth = 15.5 feet.

Distance traveled down = 7 × 2.5 = 17.5 feet.

Final depth of water surface = Initial depth + Distance traveled down.

Final depth of water surface = 15.5 feet + 17.5 feet.

Final depth of water surface = 33 feet.

Thus, 33 is the integer represents her location relative to the surface after 7 seconds.

Now, to get how far does the diver have to go to return to the surface:

As, the diver goes to 33 feet down to the surface.

Thus, the diver to return she have to go through the same distance.

So, to return to the surface she need to go to 33 feet far.

Therefore, 33 is the integer that represents her location relative to the surface after 7 seconds.

And 33 feet far the diver have to go to return to the surface.

Answer from: Quest

add an image

step-by-step explanation:

Answer from: Quest

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

$x^2-2x+y^2-6y=26$

we now create space between the x and y terms with parenthesis.

$(x^2-2x)+(y^2-6y)=26$

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

$\frac{-2}{2} =(-1)^{2} =1$

$\frac{-6}{2} =(-3)^{2} =9$

we add the squares to both sides.

$(x^2-2x+1)+(y^2-6y+9)=26+1+9$

simplify.

$(x^2-2x+1)+(y^2-6y+9)=36$

and write the quadratics in factored form.

$(x-1)^{2} +(y-3)^{2} =36$

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

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