Find the distance from the point (-6,8) to the line y=-3x+10. round distance to nearest hundredths.

You use the distance distance formula d √︎(x₂-x₁)+(y₂-y₁) on this as well as y=mx+b.

With mx+b you find your second set of coordinates. With the distance formula you get your square root.

So y=-3x+10 well send you 10 up the y intercept the, neg 3 down, and positive one across the x axis.

This gives you your second set of coordinates (1,7) to go with your first set.

You apply both sets of coordinates to the distance formula. d √︎(x₂-x₁)+(y₂-y₁)

You get √︎(1-(-6))+(7-8)
Then √︎7-1
Finally √︎6

And √︎6 is between 2*2 and 3*3

Rough guess, the Sq root of 6 is 2.449 or rounded to the hundredth 2.45

The answer is 63.!