Given that the nth term tn of a sequence is tn=2n+5 find
the 5th term
the 8th term
the lowest common multiple of the 5ht and the 8th term
of the sequence

The lowest common multiple of the 5th term  and the 8th term of the sequence is 3

Step-by-step explanation:

Given that the nth term Tn of a sequence is

To find the 5th terms of the sequence

put n=5 in (1) we get

The lowest common multiple of 5th term of the sequences are 3 and 5

To find the 8th terms of the sequence

put n=8 in (1) we get

The lowest common multiple of 8th term  of the sequence are 3 and 7

Therefore the lowest common multiple of 5th and 8th term of the sequence is 3

i wish i could you, i have no idea how to answer this

step-by-step explanation:

answer is because 4×10=40

and 98×4= is 392

40,392