9. the perimeter of a rectangle iş 24 meters. the width is 30 meters less than five
times the length. find the dimensions of the rectangle

length of rectangle=7 metre

width of rectangle=5 metre

Step-by-step explanation:

perimeter of rectangle=2(length+width)

given perimeter of rectangle=p=24

let, length of rectangle=l

width of rectangle=b=5l-30

ac/ques, p=2(l+b)

24=2(l+5l-30)

12=6l-30

42=6l

l=

l=7 metre

b=35-30=5 metre

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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step-by-step explanation: