Suppose that in the maintenance of a large medical-records file for insurance purposes the probability of an error in processing is 0.0010, the probability of an in filing is 0.0009, the probability of an error in retrieving is 0.0012, the probability of an error in processing as well as filing is 0.0002, the probability of an error in processing as well as retrieving is 0.0003, and the probability of an error in processing and filing as well as retrieving is 0.0001. what is the probability of making at least one of these errors? (p(r intersection f)=0.0002) be sure to draw a venn diagram.

The probability of making at least one of these errors is 0.0025

Step-by-step explanation:

Consider the provided information.

Let P represents the error in processing.

Let F represents the error in filling.

Let R represents the error in retrieving.

The probability of an error in processing is 0.0010: P(P) = 0.0010

The probability of an in filing is 0.0009: P(F) = 0.0009

The probability of an error in retrieving is 0.0012: P(R) = 0.0012,

The probability of an error in processing as well as filing is 0.0002:

P(P∩F) = 0.0002

The probability of an error in processing as well as retrieving is 0.0003,

P(P∩R) = 0.0003

The probability of an error in processing and filing as well as retrieving is 0.0001.

P(P∩F∩R)=0.0001

P(R∩F)=0.0002

The probability of at least one is:

P(P∪F∪R)=P(P)+P(R)+P(F)-P(P∩F)-P(P∩R)-P(R∩F)+P(P∩F∩R)

P(P∪F∪R)=0.0010+0.0009+0.0012-0.0002-0.0002-0.0003+0.0001

P(P∪F∪R)=0.0025

Hence, the probability of making at least one of these errors is 0.0025

The required diagram is shown below.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

at home andrea has 1 2/3 kilograms of rice

step-by-step explanation: