Suppose diane and jack are each attempting to use a simulation to describe the sampling distribution from a population that is skewed right with mean 70 and standard deviation 15. diane obtains 1000 random samples of size nequals4 from the population, finds the mean of the means, and determines the standard deviation of the means. jack does the same simulation, but obtains 1000 random samples of size nequals40 from the population. (a) describe the shape you expect for jack’s distribution of sample means. describe the shape you expect for diane’s distribution of sample means.

(b) what do you expect the mean of jack’s distribution to be? what do you expect the mean of diane’s distribution to be?

(c) what do you expect the standard deviation of jack’s distribution to be? what do you expect the standard deviation of diane’s distribution to be?

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.