250
250
pengunis marched there was 
1
1
in the first row 
a
d

2
a
d

2
in the 
2
2
rowand 
3
3
in the 
3
3
row andthepattern continued through all he rowshowmny rows where there
evaluate

You can solve it using an arithmetic sequence.

The nth term of the sequence is equal to the number of penguins in the nth row. It's equal to the number of the row.

There was one penguin in the first row.

The sum of the sequence:

There were 250 penguins - set the sum equal to 250 and solve:

The number of rows can't be a negative number so n≈21.87.

So, there were 21 full rows and one not full.

Calculate the number of penguins in 21 rows:

There were 19 penguins in the last row.

The

There were 22 rows of penguins. The last row wasn't full, it contained 19 penguins.

Step-by-step explanation:

congruent segments

step-by-step explanation:

42.4

step-by-step explanation:

convert to decimal